Integral of (sin (x))^1/2)(cos^3(x)) dx

Then du = 1/x dx. The integral then becomes \int {\sqrt{sin(u)}} du. From here, use the identity that sin(x) = sin(u) and rewrite the integral as \int {\sqrt{sin(x)}} dx. Then use the same method as the previous problem to solve for the integral.
  • #1
Jeann25
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Not really sure where to begin on this integral. Hope this reads alright on here.

Integral of (sin (x))^1/2)(cos^3(x)) dx
 
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  • #2
[tex] \int {\sqrt{sin(x)}} cos(x)^3 dx [/tex]

Convert this into

[tex] \int {\sqrt{sin(x)}}cos^2(x)cos(x) [/tex].

From your identities in trignometry

[tex] cos^2(x) = 1 - sin^2(x) [/tex].

This will leave you with all sine terms and one cosine term once you rewrite cosine squared. Do you see what to do from here?
 
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  • #3
That was very helpful, thank you. Could I also get help with this one pls? :) I just seem to have a hard time figuring out where to start on these.

The integral of (sin(ln x))/x dx
 
  • #4
Jeann25 said:
That was very helpful, thank you. Could I also get help with this one pls? :) I just seem to have a hard time figuring out where to start on these.

The integral of (sin(ln x))/x dx

Use a substitution letting u = ln x.
 

FAQ: Integral of (sin (x))^1/2)(cos^3(x)) dx

What is the formula for the integral of (sin(x))^1/2)(cos^3(x)) dx?

The formula for the integral of (sin(x))^1/2)(cos^3(x)) dx is ∫ (sin(x))^1/2 (cos^3(x)) dx = -2/5 (cos^2(x))^3/2 + C.

How do you solve the integral of (sin(x))^1/2)(cos^3(x)) dx?

To solve the integral of (sin(x))^1/2)(cos^3(x)) dx, you can use the substitution method by setting u = sin(x) and du = cos(x) dx. You can also use the trigonometric identity sin^2(x) + cos^2(x) = 1 to simplify the integral.

What is the domain of the integral of (sin(x))^1/2)(cos^3(x)) dx?

The domain of the integral of (sin(x))^1/2)(cos^3(x)) dx is all real numbers.

Can you solve the integral of (sin(x))^1/2)(cos^3(x)) dx without using substitution?

Yes, you can also use integration by parts to solve the integral of (sin(x))^1/2)(cos^3(x)) dx. Set u = (sin(x))^1/2 and dv = cos^3(x) dx, and then use the formula ∫ u dv = u v - ∫ v du.

What are the applications of the integral of (sin(x))^1/2)(cos^3(x)) dx?

The integral of (sin(x))^1/2)(cos^3(x)) dx has applications in physics, engineering, and other fields that involve calculating areas under curves or finding the average value of a function over a specific interval. It can also be used to solve differential equations and in finding antiderivatives of more complex trigonometric functions.

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