- #1
iScience
- 466
- 5
im trying to find...
∫te^(5t)dt
i did integration by parts..
u=e^5t
dv=tdt
∫te^(5t)dt={e^(5t)}(t)-5∫(t){e^(5t)}dt
collected the integral terms on one side to get..
6∫te^(5t)dt={e^(5t)}(t)
∫te^(5t)dt= {e^(5t)}(t)/6
but wolfram alpha says otherwise. they don't give out the steps freely anymore. please help
∫te^(5t)dt
i did integration by parts..
u=e^5t
dv=tdt
∫te^(5t)dt={e^(5t)}(t)-5∫(t){e^(5t)}dt
collected the integral terms on one side to get..
6∫te^(5t)dt={e^(5t)}(t)
∫te^(5t)dt= {e^(5t)}(t)/6
but wolfram alpha says otherwise. they don't give out the steps freely anymore. please help