- #1
christian0710
- 409
- 9
Hi, I'm trying to understand why
When you write a*dt = dv then you can write the integral like this.,
∫dv (from v0 to vt) = ∫a*dt (from 0 to t)
My challenge is this: from the equation a*dt = dv, the term "dv" geometrically means an infenitesimalle small change in function value of the function v(t), so dv must be an integer. So you are integrating an integer, dv, and the graph of an integer is a straight horizontal line on the v(t) vs t axis. so is it correctly understood that if we assume dv= 1 then the integral of dv should just be v. But here is the part i don't understand, the lower and upper bounds are v0 and v, usually the limits of integration are limits on the x-axis and Not on the Y-axis (or V(t) axis), so should i interprete dv as an integer whose function has Velocity on the x axis? This just does not make sense to me,
Here is a photo of what is written in the book.,
When you write a*dt = dv then you can write the integral like this.,
∫dv (from v0 to vt) = ∫a*dt (from 0 to t)
My challenge is this: from the equation a*dt = dv, the term "dv" geometrically means an infenitesimalle small change in function value of the function v(t), so dv must be an integer. So you are integrating an integer, dv, and the graph of an integer is a straight horizontal line on the v(t) vs t axis. so is it correctly understood that if we assume dv= 1 then the integral of dv should just be v. But here is the part i don't understand, the lower and upper bounds are v0 and v, usually the limits of integration are limits on the x-axis and Not on the Y-axis (or V(t) axis), so should i interprete dv as an integer whose function has Velocity on the x axis? This just does not make sense to me,
Here is a photo of what is written in the book.,