Integrands that vanish everywhere

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In summary, in physics, the assumption is often made that if the integral of a function over any region in space is equal to zero, then the function must vanish everywhere in space. This is because if the function did not vanish in some region, the integral would not be equal to zero. However, it is possible for the function to be non-zero on a set of measure zero, which may not concern physicists. It is also possible to show that the function must vanish at every point if it is continuous.
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In physics, we often use the assumption that if the integral:

[tex]\int_D f(\vec x) d \vec x =0[/tex]

and this holds for any region D in the space, then the integrand must vanish identically everywhere in the space. This was motivated by the argument that if it didn't vanish in some region, we could focus the integrand in that region (say, only where it is positive) and the above equation wouldn't hold. But I was thinking, wouldn't this argument only show that the integrand vanishes almost everywhere. That is, it could still be non-zero on a set of measure zero, and the above equation would still always be satisfied. Is it just that this possibility doesn't concern physicists, or is there actually a way to show it must vanish at every point?
 
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Actually, now I see that the argument would work if the function were continuous, because then if there was any point x where f(x) were non-zero, say positive, it would have a neighborhood where f was positive, and so we could integrate over that neighborhood to get a non-zero value. That's good enough for me. You can delete this thread if you want.
 
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This is an interesting question and brings up an important point in mathematical reasoning and the use of assumptions in physics. It is true that in mathematics, the assumption that an integral vanishes for all regions would only imply that the integrand vanishes almost everywhere. However, in physics, we often make certain assumptions and simplifications in order to make our calculations and models more manageable. In this case, the assumption that the integrand vanishes everywhere is a simplification that is often used in physics because it simplifies the analysis and allows us to make predictions and draw conclusions more easily.

In addition, in physics, we are often dealing with continuous functions and physical quantities that have a physical meaning and interpretation. Therefore, even if the integrand is non-zero on a set of measure zero, it would not have any physical significance and would not affect our conclusions and predictions. This is because physical measurements and observations are always subject to some level of uncertainty and error, and we can only measure and observe physical quantities up to a certain precision.

Furthermore, in physics, we often use a combination of mathematical reasoning and experimental data to validate our assumptions and models. If the assumption that the integrand vanishes everywhere leads to predictions and results that are consistent with experimental data, then it is considered a valid assumption in the context of physics.

In summary, while the mathematical argument may suggest that the integrand only vanishes almost everywhere, the assumption that it vanishes everywhere is a simplification that is often used in physics for practical and pragmatic reasons. As long as this assumption leads to consistent and accurate predictions, it is considered a valid assumption in the context of physics.
 

FAQ: Integrands that vanish everywhere

What does it mean for an integrand to "vanish everywhere"?

When an integrand vanishes everywhere, it means that the function is equal to zero for all values of the independent variable. In other words, the graph of the function lies on or below the x-axis for all x-values.

Can an integrand that vanishes everywhere still have a non-zero integral?

Yes, it is possible for an integrand to vanish everywhere but still have a non-zero integral. This can occur if the function oscillates between positive and negative values, resulting in a net cancellation when integrated over a certain interval.

How do integrands that vanish everywhere affect the overall integral?

If an integrand vanishes everywhere, it will have no contribution to the overall integral. This means that the integral will be equal to zero, regardless of the bounds of integration or the shape of the function.

Are there any practical applications of integrands that vanish everywhere?

Yes, integrands that vanish everywhere can be useful in certain mathematical proofs and calculations. They also have applications in physics, particularly in the study of waves and interference phenomena.

Is the concept of an integrand that vanishes everywhere unique to one-dimensional integrals?

No, the concept of an integrand that vanishes everywhere can also apply to multi-dimensional integrals, where the function must equal zero in all dimensions for the integral to be equal to zero.

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