Integrate Volumes: Revolve Region Bounded by x=0, x=1, y=0, y=x^5

In summary, the formula for finding the volume of a solid of revolution is V = π∫<sub>a</sub><sup>b</sup>(f(x))<sup>2</sup>dx. The region to be revolved is identified by the boundaries of the integral, and can be a triangular region in the first quadrant. A solid of revolution is different from a solid of known cross-section in terms of how they are created and their surface. To set up the integral for finding the volume of a solid of revolution, the formula is used and the boundaries and function are plugged in. The same region can be revolved around different axes, affecting the resulting solid and the method for finding its volume.
  • #1
physicsnewb7
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Homework Statement


Revolve the region bounded by x=0, x=1, y=0 and y=x^5 about the y-axis use shells to find the volume

I know how to set up the integral I just don't know where I'm integrating from. Is it from 0 to 1?
 
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  • #2
Hi physicsnewb7! :smile:

You can use "horizontal" strips, to give you disc shells, or "vertical" strips, to give you cylindrical shells …

in either case, use the endpoints of the strip. :wink:
 
  • #3
thank you tiny tim
 

FAQ: Integrate Volumes: Revolve Region Bounded by x=0, x=1, y=0, y=x^5

1) What is the formula for finding the volume of a solid of revolution?

The formula for finding the volume of a solid of revolution is V = π∫ab(f(x))2dx, where a and b are the limits of integration and f(x) is the function defining the shape of the solid.

2) How do you identify the region to be revolved?

The region to be revolved is identified by the boundaries of the integral, which in this case are x=0, x=1, y=0, and y=x^5. These boundaries form a triangular region in the first quadrant.

3) What is the difference between a solid of revolution and a solid of known cross-section?

A solid of revolution is created by rotating a shape around an axis, while a solid of known cross-section is created by stacking slices of a shape along an axis. A solid of revolution has a curved surface, while a solid of known cross-section has a flat surface.

4) How do you set up the integral for finding the volume of a solid of revolution?

The integral is set up by using the formula V = π∫ab(f(x))2dx and plugging in the boundaries of the region to be revolved and the function that defines the shape of the solid. In this case, the boundaries are x=0, x=1, and the function is y=x^5.

5) Can the same region be revolved around different axes?

Yes, the same region can be revolved around different axes to create different solids. The choice of axis will affect the shape and symmetry of the resulting solid, as well as the method for setting up the integral to find its volume.

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