Integrating a Circle: Troubleshooting Simple Experiments

In summary, the conversation discusses a problem with calculating the area of a circle using integration, specifically the function and integral provided by Wolfram. The conversation suggests using a limit as x approaches the radius and using polar coordinates for the integral to get the correct answer. The issue is resolved by setting the calculator to use radians and adjusting the limits.
  • #1
tuoni
61
0
Just started learning integration, and although I can manage simple stuff, I've run into problems with some experiments of mine.

http://enes.fi/temp/circle.png

The function for a circle is:

[itex]y = \sqrt{r^{2} - x^{2}}[/itex]

; and Wolfram gives the integral as:

[itex]\frac{1}{2}\left[x \cdot \sqrt{r^{2} - x^{2}} + r^{2} \cdot tan^{-1} \left(\frac{x}{\sqrt{r^{2} - x^{2}}}\right)\right][/itex]

This in turn results in:

[itex]f(b) - f(a) = f(s) - 0[/itex]

However, it's all wrong!

A radius of 10 means the area is approximately 78.540. Plugging in 10 into the equation results in division by zero. Even trying to integrate from 0 to 1, I get an area of 291.934, when it should be slightly less than 10!

Grrr! What am I doing wrong?
 
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  • #2
you have to take a limit as x -> r then you get the right answer

what you should do is do the integral in polar coordinates
 
  • #3
Thank you!

Setting my calculator to use rad (was set on deg) and using limits made it work.
 

FAQ: Integrating a Circle: Troubleshooting Simple Experiments

What are some common errors when integrating a circle in a simple experiment?

Some common errors when integrating a circle in a simple experiment include not starting with the correct equation, not correctly identifying the variables and limits of integration, and making mistakes in the integration process itself.

How can I avoid errors when integrating a circle in a simple experiment?

To avoid errors when integrating a circle in a simple experiment, make sure to double check your equation and variables before starting the integration process. Also, take your time and carefully follow each step of the integration process to ensure accuracy.

What should I do if my integration results in a negative value for the area of the circle?

If your integration results in a negative value for the area of the circle, it is likely that you have incorrectly identified the limits of integration or made a mistake in the integration process. Double check your work and make any necessary corrections.

Are there any shortcuts or tricks for integrating a circle in a simple experiment?

There are some shortcuts or tricks that can be used when integrating a circle in a simple experiment, such as using symmetry to reduce the amount of work needed or using trigonometric identities to simplify the integration process. However, it is important to understand the underlying concepts and steps of integration to ensure accuracy.

Can I use numerical methods to integrate a circle in a simple experiment?

Yes, numerical methods such as the trapezoidal rule or Simpson's rule can be used to integrate a circle in a simple experiment if the equation is too complex to integrate by hand. However, these methods may not be as accurate as analytical integration and may require more computational power.

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