Integrating a Spherical Coordinate Problem

In summary, we are evaluating the integral \iiint 8-x^2-y^2\,dx\,dy\,dz, where H is the solid hemisphere x^2 + y^2 + z^2 ≤ 9, z ≤ 0. The attempt at a solution involves setting up the integral in polar coordinates and using the substitution x= \rho cos(\theta)sin(\phi) and y= \rho sin(\theta)sin(\phi). The correct expression for x^2+y^2 is \rho^2 sin^2(\phi), not 2\rho^2 sin^2(\phi). The limits for this integral are correct for the given question.
  • #1
yaho8888
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Homework Statement



Evaluate the integral below, where H is the solid hemisphere x^2 + y^2 + z^2 ≤ 9, z ≤ 0

[tex]\iiint 8-x^2-y^2\,dx\,dy\,dz[/tex].

Homework Equations



none

The Attempt at a Solution



[tex]\int_{0}^{2\pi} \int_{\frac{\pi}{2}}^{\pi} \int_{0}^{3} (8-2p^2 \sin^2{\phi}) p^2 \sin{\phi}\ ,dp\,d\phi\, d\theta [/tex]

do I set up the integral right?
 
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  • #2
In polar coordinates [itex]x= \rho cos(\theta)sin(\phi)[/itex] and [itex]y= \rho sin(\theta)sin(\phi)[/itex] so
[tex] x^2+ y^2= \rho^2 cos^2(\theta) sin^2(\phi)+ \rho^2 sin^2(\theta) sin^2(\phi)[/tex]
[tex]= \rho^2 sin^2(\phi)(cos^2(\theta)+ sin^2(\theta))= \rho^2 sin^2(\phi)[/tex]
NOT "[itex]2\rho^2 sin^2(\phi)[/itex].
 
  • #3
ye! sorry. 8-p^2*sin^2(phi)

but if I use [tex]= \rho^2 sin^2(\phi)[/tex] are the limit of this integral right for the question stated above.
 

FAQ: Integrating a Spherical Coordinate Problem

What are spherical coordinates?

Spherical coordinates are a system of three-dimensional coordinates that are used to locate a point in space by specifying its distance from a fixed origin, its inclination angle from the positive z-axis, and its azimuthal angle from the positive x-axis.

How do you convert spherical coordinates to Cartesian coordinates?

To convert spherical coordinates to Cartesian coordinates, you can use the following equations:
x = r * sin(θ) * cos(φ)
y = r * sin(θ) * sin(φ)
z = r * cos(θ)
where r is the distance from the origin, θ is the inclination angle, and φ is the azimuthal angle.

What is the difference between spherical and cylindrical coordinates?

Spherical coordinates use an inclination angle and an azimuthal angle to locate a point in space, while cylindrical coordinates use a height, an angle, and a distance from the z-axis. Spherical coordinates are often used to describe objects in three-dimensional space, while cylindrical coordinates are commonly used in physics and engineering.

How are spherical coordinates used in real-world applications?

Spherical coordinates are commonly used in physics, engineering, and mathematics to describe the motion and position of objects in three-dimensional space. They are also used in navigation, astronomy, and geology to specify the location of points on the Earth's surface or in the sky.

What are some advantages of using spherical coordinates?

One advantage of using spherical coordinates is that they can easily describe objects with spherical symmetry, such as planets or stars. They are also useful for solving certain types of differential equations and can simplify calculations in certain applications, such as electromagnetism and fluid dynamics.

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