Integrating arcsin(x^2) using u-substitution and integration by parts

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In summary, the general formula for integrating 2x[arcsin(x^2)]dx is ∫2x[arcsin(x^2)]dx = x^2arcsin(x^2) + C. The process for solving this integral involves using integration by parts, with u = arcsin(x^2) and dv = 2x dx. The arcsin function is significant in this integral as it is the derivative of sin(x), making it necessary for integration by parts. However, it can also be solved using substitution. Real-world applications of this integral include physics, such as calculating the motion of objects under gravity, and in solving differential equations and finding the area of curves.
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Jayy962
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The title contains the problem I have difficulty with.

I understand I must use u substitution and then integrate by parts.

So my actual problem is: How do I find the derivative of arcsin(x^2) if u = arcsin(x^2)?


I know the derivative of arcsin(x^2) is 1/(1-x^2)^1/2


Thanks for helping. I hope this is detailed enough.
 
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What I recommend is let u=x^2. Then do integration by parts with v=arcsin(u) and dw=du.
 

FAQ: Integrating arcsin(x^2) using u-substitution and integration by parts

What is the general formula for integrating 2x[arcsin(x^2)]dx?

The general formula for integrating 2x[arcsin(x^2)]dx is ∫2x[arcsin(x^2)]dx = x^2arcsin(x^2) + C, where C is the constant of integration.

What is the process for solving the integral of 2x[arcsin(x^2)]dx?

The process for solving the integral of 2x[arcsin(x^2)]dx involves using integration by parts, where u = arcsin(x^2) and dv = 2x dx. This results in the formula ∫2x[arcsin(x^2)]dx = x^2arcsin(x^2) - ∫x^2 * (1/sqrt(1-x^4)) * dx, which can then be solved using substitution or other integration techniques.

What is the significance of the arcsin function in this integral?

The arcsin function, also known as the inverse sine function, is used in this integral because it is the derivative of sin(x). It is necessary in order to solve the integral using integration by parts.

Can this integral be solved without using integration by parts?

Yes, this integral can also be solved using substitution. By letting u = x^2, we can rewrite the integral as ∫2x[arcsin(x^2)]dx = ∫arcsin(u) * du, which can then be solved using simple integration rules.

What are some real-world applications of this integral?

This integral has various applications in physics, particularly in calculating the motion of objects under the influence of gravity. It is also used in calculating the area of curves and in solving differential equations.

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