- #1
trajan22
- 134
- 1
hi I am having trouble integrating arctan(u).
i have no idea where to even start. i know the derivative of arctan is
[tex] \frac{1}{x^2+1} [/tex] so i would assume that the integral would be the opposite?
but i am supposed to prove that [tex] (arctan(u))=u(arctan(u))-\frac{1}{2}ln(1+u^2)+C [/tex]
i am completely lost please help...any input is much appreciated.
i have no idea where to even start. i know the derivative of arctan is
[tex] \frac{1}{x^2+1} [/tex] so i would assume that the integral would be the opposite?
but i am supposed to prove that [tex] (arctan(u))=u(arctan(u))-\frac{1}{2}ln(1+u^2)+C [/tex]
i am completely lost please help...any input is much appreciated.