- #1
Kuma
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Homework Statement
Okay this is part of a much bigger double integral, but I have hit a roadblock here.
[tex]\int[/tex]x1/u (top), 0 (bottom). (1-(x1/u))^a2 -1 ((x1/u) - x1)^a3 - 1
Homework Equations
integration by parts/substitution?
The Attempt at a Solution
so first i set up an integration by parts here with
du = (1-(x1/u))^a2 -1
and
v = ((x1/u) - x1)^a3 - 1
i found out dv and to find out u i had to integrate that first part. So now I am stuck because this is a reverse chain rule i believe, so i set up a substitution with t = 1-(x1/u) and found out dt = x1/u^2 du. However i keep getting the wrong answer, any help?