Integrating $\frac{x^2}{(1+x^2)^3}$ Over the Real Line

I don't provide solutions to homework problems, but here's a summary of the conversation:In summary, the function $\frac{x^2}{(1+x^2)^3}$ has a pole of order 3 in the upper half plane at $z=i$, which can be used to evaluate the integral over the real line. A possible approach is to use a tan substitution, although this may not have been the expected solution.
  • #1
Fermat1
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integrate $\frac{x^2}{(1+x^2)^3}$ over the real line
 
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  • #2
Fermat said:
integrate $\frac{x^2}{(1+x^2)^3}$ over the real line

[sp]The function has in the upper half plane a pole of order 3 in z=i, so that is...

$\displaystyle \int_{- \infty}^{+ \infty} \frac{x^{2}}{(1 + x^{2})^{3}}\ d x = 2\ \pi i\ \lim_{z \rightarrow i} \frac{1}{2}\ \frac {d^{2}}{d z^{2}}\ \frac{z^{2}}{(z+i)^{3}} = \frac{\pi}{8}$[/sp]


Kind regards

$\chi$ $\sigma$
 
  • #3
chisigma said:
[sp]The function has in the upper half plane a pole of order 3 in z=i, so that is...

$\displaystyle \int_{- \infty}^{+ \infty} \frac{x^{2}}{(1 + x^{2})^{3}}\ d x = 2\ \pi i\ \lim_{z \rightarrow i} \frac{1}{2}\ \frac {d^{2}}{d z^{2}}\ \frac{z^{2}}{(z+i)^{3}} = \frac{\pi}{8}$[/sp]


Kind regards

$\chi$ $\sigma$

that is a way I had no really expected (although it is correct). What about a tan substitution
 
  • #4
Fermat said:
integrate $\frac{x^2}{(1+x^2)^3}$ over the real line

Is this a homework problem?
Suspecting that this is a homework problem, I leave a hint, use $x=\tan\theta$. The resulting integral is straightforward.
 
  • #5


I would approach this problem by first understanding the function we are integrating. The function $\frac{x^2}{(1+x^2)^3}$ is a rational function, meaning it is a ratio of two polynomials. It also has a singularity at $x=0$ since the denominator becomes zero at that point.

Next, I would consider the limits of integration, which in this case is over the real line. This means we need to integrate from $-\infty$ to $\infty$. This is known as an improper integral, since the limits extend to infinity.

To solve this integral, I would use techniques such as substitution or partial fractions to simplify the function and make it easier to integrate. I would then evaluate the integral using the Fundamental Theorem of Calculus or other integration rules.

However, since the function has a singularity at $x=0$, we need to be careful when evaluating the integral. We would need to use a technique called Cauchy's principal value, which involves taking the limit as the singularity approaches $x=0$ from both sides.

Overall, integrating $\frac{x^2}{(1+x^2)^3}$ over the real line is a challenging problem, but with proper techniques and careful consideration of the singularity, it can be solved. This integral may have applications in physics, engineering, or other scientific fields, so understanding how to solve it is important for further research and analysis.
 

FAQ: Integrating $\frac{x^2}{(1+x^2)^3}$ Over the Real Line

What is the integrand in the given integral?

The integrand is x^2/(1+x^2)^3.

What is the domain of integration in this problem?

The domain of integration is the set of all real numbers, since the integral is being evaluated over the real line.

Is this integral convergent or divergent?

This integral is convergent since the integrand is a continuous function and the domain of integration is the entire real line.

What method can be used to evaluate this integral?

This integral can be evaluated using integration by parts or by using a trigonometric substitution.

What is the value of this integral?

The value of this integral is -1/2.

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