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integrate $\frac{x^2}{(1+x^2)^3}$ over the real line
Fermat said:integrate $\frac{x^2}{(1+x^2)^3}$ over the real line
chisigma said:[sp]The function has in the upper half plane a pole of order 3 in z=i, so that is...
$\displaystyle \int_{- \infty}^{+ \infty} \frac{x^{2}}{(1 + x^{2})^{3}}\ d x = 2\ \pi i\ \lim_{z \rightarrow i} \frac{1}{2}\ \frac {d^{2}}{d z^{2}}\ \frac{z^{2}}{(z+i)^{3}} = \frac{\pi}{8}$[/sp]
Kind regards
$\chi$ $\sigma$
Fermat said:integrate $\frac{x^2}{(1+x^2)^3}$ over the real line
The integrand is x^2/(1+x^2)^3
.
The domain of integration is the set of all real numbers, since the integral is being evaluated over the real line.
This integral is convergent since the integrand is a continuous function and the domain of integration is the entire real line.
This integral can be evaluated using integration by parts or by using a trigonometric substitution.
The value of this integral is -1/2
.