- #1
physguy09
- 19
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So I need to inegrate over a solid angle, in which every possible orientation is considered (we are doing scattering events in which we assume every possible angle is possible), thus I need to solve
[tex]\int d\Omega_1 d\Omega_2 d\Omega_3[/tex] Eqn (1).
Now I know
[tex]\int^{2 \pi}_{0} \int^{\pi}_{0}d\Omega = \int^{2 \pi}_{0} \int^{\pi}_{0} sin(\theta)d\theta d\phi = 2\pi \int^{\pi}_{0} sin(\theta) d\theta = 2\pi (-cos(\theta))^{\pi}_{0} = 4 \pi[/tex]
so shouldn't that mean that Eqn (1) should integrate to [tex] 64 \pi^3[/tex]?
[tex]\int d\Omega_1 d\Omega_2 d\Omega_3[/tex] Eqn (1).
Now I know
[tex]\int^{2 \pi}_{0} \int^{\pi}_{0}d\Omega = \int^{2 \pi}_{0} \int^{\pi}_{0} sin(\theta)d\theta d\phi = 2\pi \int^{\pi}_{0} sin(\theta) d\theta = 2\pi (-cos(\theta))^{\pi}_{0} = 4 \pi[/tex]
so shouldn't that mean that Eqn (1) should integrate to [tex] 64 \pi^3[/tex]?
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