- #1
opticaltempest
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I am trying to evaluate the following integral.
[tex]\int_{-\infty}^{\infty}{\delta(2t-3)\sin(\pi t) dt}[/tex]
where delta represents the Dirac delta function.
I am told that the answer is -1. However, when I evaluate it in MATLAB and Maple 11, I get an answer of -1/2. What is the correct way to evaluate this integral by hand? Which answer is correct?
[tex]\int_{-\infty}^{\infty}{\delta(2t-3)\sin(\pi t) dt}[/tex]
where delta represents the Dirac delta function.
I am told that the answer is -1. However, when I evaluate it in MATLAB and Maple 11, I get an answer of -1/2. What is the correct way to evaluate this integral by hand? Which answer is correct?