Integration: 1/((x^(1/2)-x^(1/3))

In summary, the conversation discusses a problem of integrating 1/(sqrt(x)-cbrt(x)), with instructions provided on how to solve it by substituting u^6 for x and then integrating the resulting expression. The conversation also mentions a resource for formatting equations in LaTeX.
  • #1
Bohn507
4
0
I have no idea where to start with this. Sorry about the format, I don't know where to make it into an easier to read style.

1/((x^(1/2)-x^(1/3))
 
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  • #2
The problem is: [itex]\int \dfrac{1}{\sqrt{x} - \sqrt[3]{x}} dx[/itex]

Here, http://www.wolframalpha.com/input/?i=integrate+1%2F((x^(1%2F2)-x^(1%2F3))
Click on show steps and that's it.

See LaTeX for formatting your equations here.
 
  • #3
Thank you!
 
  • #4
Or, you could do as follows:
Introduce:
[tex]x=u^{6}\to\frac{dx}{du}=6u^{5}\to{dx}=6u^{5}du[/tex]
Then,
[tex]\int\frac{dx}{\sqrt{x}-\sqrt[3]{x}}=\int\frac{6u^{5}}{u^{3}-u^{2}}du=\int\frac{6u^{3}}{u-1}du=6\int({u}^{2}+u+1+\frac{1}{u-1})du[/tex]
which is easily integrated.
 

FAQ: Integration: 1/((x^(1/2)-x^(1/3))

What is integration?

Integration is a mathematical process that involves finding the area under a curve on a graph. It is the inverse operation of differentiation, and it is used to solve a variety of problems in mathematics, physics, and engineering.

What is the function 1/((x^(1/2)-x^(1/3))?

1/((x^(1/2)-x^(1/3)) is a rational function that is commonly used in calculus and applied mathematics. It is also known as a "difference of roots" function and has a variety of applications in areas such as optimization, physics, and finance.

Why is integration of 1/((x^(1/2)-x^(1/3)) important?

Integration of 1/((x^(1/2)-x^(1/3)) is important because it allows us to solve a wide range of problems that involve finding the area under a curve. It is also a fundamental concept in calculus and is used extensively in engineering, physics, and economics.

How do you integrate 1/((x^(1/2)-x^(1/3))?

The integration of 1/((x^(1/2)-x^(1/3)) can be solved using various methods, such as substitution, integration by parts, or partial fractions. It is a complex integral and may require advanced techniques to solve. It is important to carefully follow the steps and rules of integration to arrive at the correct solution.

What are the practical applications of integrating 1/((x^(1/2)-x^(1/3))?

The integration of 1/((x^(1/2)-x^(1/3)) has numerous practical applications, such as finding the volume of irregular shapes, calculating work and power in physics, and computing the expected value in finance. It is also used in various engineering problems, such as determining the center of gravity and moments of inertia.

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