- #1
Ren Figueroa
- 2
- 0
Hi guys.
I’m looking at the brute force way at getting the E-field for a uniformly spherical charge distribution. The location of the E-field of interest is anywhere outside of the sphere. Here are some images
Everything makes sense. I’m just not sure why the bounds for ‘s’ where z-r to z+r. From my perspective, z+r is the left hemisphere while z-r is the right hemisphere because we can consider the relationship between s, r, and z from the vector relation s=z-r. If i set the positive axis to point to the left, if sort of makes sense to integrate from z+r to z-r but this would obviously yield a negative result. So, I’m curious about detmining the proper bounds.
I’m looking at the brute force way at getting the E-field for a uniformly spherical charge distribution. The location of the E-field of interest is anywhere outside of the sphere. Here are some images
Everything makes sense. I’m just not sure why the bounds for ‘s’ where z-r to z+r. From my perspective, z+r is the left hemisphere while z-r is the right hemisphere because we can consider the relationship between s, r, and z from the vector relation s=z-r. If i set the positive axis to point to the left, if sort of makes sense to integrate from z+r to z-r but this would obviously yield a negative result. So, I’m curious about detmining the proper bounds.