- #1
AStaunton
- 105
- 1
the expression to integrate is:
[tex]\int x^{3}e^{x^{2}}dx[/tex]
and in the spirit of "LIATE" I set my u and dv as the following:
[tex]dv=e^{x^{2}}dx[/tex]
[tex]u=x^{3}[/tex]
however, doing this that I integrate [tex]dv=e^{x^{2}}dx[/tex] in order to get v...and unless I'm missing something, this does not seem like an easy integral! a u substition won't work as i'd need an x^1 term multiplying by the e^x^2...
and going the other way and setting dv=x^3dx and u=e^x^2 and plugging into int,by parts formula gets:
[tex]\frac{x^{4}}{4}e^{x^{2}}-\int\frac{x^{4}}{4}2xe^{x^{2}}dx[/tex]
and I don't think further integration by parts will help with this new integral..
any advice appreciated.
[tex]\int x^{3}e^{x^{2}}dx[/tex]
and in the spirit of "LIATE" I set my u and dv as the following:
[tex]dv=e^{x^{2}}dx[/tex]
[tex]u=x^{3}[/tex]
however, doing this that I integrate [tex]dv=e^{x^{2}}dx[/tex] in order to get v...and unless I'm missing something, this does not seem like an easy integral! a u substition won't work as i'd need an x^1 term multiplying by the e^x^2...
and going the other way and setting dv=x^3dx and u=e^x^2 and plugging into int,by parts formula gets:
[tex]\frac{x^{4}}{4}e^{x^{2}}-\int\frac{x^{4}}{4}2xe^{x^{2}}dx[/tex]
and I don't think further integration by parts will help with this new integral..
any advice appreciated.