- #1
physicsfan24
- 7
- 0
Question:
[tex]\int^{1}_{-1} \frac{dx}{(1+x^4)} [/tex]
I attempt:
u = x^2,
so x= u^1/2
dx= 1/2 u^(-1/2)
Which gives me [tex]\int^{1}_{1} \frac{1}{(1+x^4)} * \frac{1}{(2u^1/2)}du[/tex], which is 0. Thats not the answer as seen by any graphing utility.
Where is this error? I do not know integration by parts. I just wish to know why my logic fails.
Any help? :/
[tex]\int^{1}_{-1} \frac{dx}{(1+x^4)} [/tex]
I attempt:
u = x^2,
so x= u^1/2
dx= 1/2 u^(-1/2)
Which gives me [tex]\int^{1}_{1} \frac{1}{(1+x^4)} * \frac{1}{(2u^1/2)}du[/tex], which is 0. Thats not the answer as seen by any graphing utility.
Where is this error? I do not know integration by parts. I just wish to know why my logic fails.
Any help? :/