Integration involving a physics problem.

In summary, the student is having trouble with the details of a calculus problem involving integrating a function with two variables. They are looking for help with the integration part and are using a trig substitution to hopefully solve it.
  • #1
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Homework Statement


Hello all! I'm currently trying to work a problem for my Physics 2 class (for engineering and science majors). The example problem deals with "Field of a charged line segment." I conceptually understand the problem, but I am having trouble with the details involving the integration.

The problem: "Positive charge Q is distributed uniformly along the y-axis between y= -a and y= +a. Find the electric field at point P on the x-axis at a distance x from the origin."

I know that [itex]\stackrel{\rightarrow}{E}[/itex]= [itex]\frac{kQ}{r^{2}}[/itex]

λ=[itex]\frac{Q}{2a}[/itex]

dQ=λdy=[itex]\frac{Q}{2a}[/itex]dy

r=[itex]\sqrt{x^{2}+y^{2}}[/itex]

therfore; dE=(k)([itex]\frac{dQ}{r^{2}}[/itex])= (k)([itex]\frac{Q}{2a}[/itex])([itex]\frac{dy}{x^{2}+y^{2}}[/itex])

E[itex]_{y}=[/itex][itex]_{-a}[/itex]∫[itex]^{+a}[/itex]dE[itex]_{y}[/itex]=0

E[itex]_{x}=[/itex][itex]_{-a}[/itex]∫[itex]^{+a}[/itex]dE[itex]_{x}[/itex]=[itex]_{-a}[/itex]∫[itex]^{+a}[/itex](k)([itex]\frac{Q}{2a}[/itex])([itex]\frac{dy}{x^{2}+y^{2}}[/itex])(cosθ)

cosθ=[itex]\frac{x}{\sqrt{x^{2}+y^{2}}}[/itex]

E[itex]_{x}=[/itex][itex]_{-a}[/itex]∫[itex]^{+a}[/itex]dE[itex]_{x}[/itex]=[itex]_{-a}[/itex]∫[itex]^{+a}[/itex](k)([itex]\frac{Q}{2a}[/itex])([itex]\frac{dy}{x^{2}+y^{2}}[/itex])([itex]\frac{x}{\sqrt{x^{2}+y^{2}}}[/itex])

simplifying and factoring out constants gives:

([itex]\frac{kQ}{2a}[/itex])[itex]_{-a}[/itex]∫[itex]^{+a}[/itex][itex]\frac{xdy}{(x^{2}+y^{2})^{3/2}}[/itex]

Here is where my problem comes in... I don't know how to integrate this. The book says "a table of integrals will help."

The solution is given to be:

E[itex]_{x}[/itex]=[itex]\frac{kQ}{x\sqrt{x^{2}+y^{2}}}[/itex]



Homework Equations





The Attempt at a Solution



I do have the latest CRC book which has integral tables in it. I looked at the general forms containing: c2+x2. The one it looked the closest to was: [itex]\frac{dx}{(c^{2}+x^{2})^{n}}[/itex]. But I'm not sure... I believe the x's may be treated as constants since I'm integrating with respect to y, but I'm not exactly sure how to go about working it. I looked a U-substitution but I get bogged down and confused by the fact that I am integrating a function that includes two variables. Any help would greatly be appreciated. Again, I understand the concept, but I'm getting confused on the calculus part of it (the integration/last step). Thank you.
 
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  • #2
It looks like a trig substitution might work. Try ##y = x\tan\theta,\, dy=x\sec^2\theta\,d\theta,\,
\sqrt{x^2+y^2}=x\sec\theta## and see if that does anything for you.
 
  • #3

FAQ: Integration involving a physics problem.

What is integration in physics?

Integration in physics refers to the process of finding the total or net effect of a changing quantity over a certain period of time or distance. It involves using calculus to find the area under a curve on a graph, which represents the changing quantity.

Why is integration important in physics?

Integration is important in physics because it allows us to analyze and understand the behavior of changing quantities, such as velocity, acceleration, and force. It helps us to determine important values and relationships in a system, and is often used to solve complex problems in various fields of physics.

How is integration used in kinematics?

In kinematics, integration is used to find the displacement, velocity, and acceleration of an object by integrating the equations of motion. It allows us to determine how these quantities change over time, and to analyze the motion of an object in more detail.

Can integration help in finding the work done by a force?

Yes, integration is often used to find the work done by a force on an object. By integrating the product of the force and displacement over a given distance, we can determine the total work done on the object by the force.

How is integration used in calculating the center of mass?

Integration is used in calculating the center of mass of an object by finding the weighted average of its individual masses. By integrating the position of each mass with respect to its distance from an axis, we can determine the location of the center of mass.

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