Integration of 1/x^2 sqrt(16-x) with substitution

In summary, the conversation is about integrating 1/x^2 * sqrt(16-x^2) using the substitution x = 4sin y. The person asks for help with continuing the integration after getting stuck at 1/16 * 1/(sin y)^2, and the other person suggests using the integral for csc^2 y and asks for the derivative of cot y.
  • #1
teng125
416
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my question is integra 1 / x^2 sqr root(16-x^2)
i use x = 4 sin y
then i got to integrate 1/16 times [1/(sin y)^2] in which i got stuck.pls help...how do i continue from there as i not sure ow to integra 1/(siny^2
 
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  • #2
[itex]\frac{1}{sin^2y}= csc^2y[/itex]- you should know the integral for that. What is the derivative of cot y?

(Sorry- I had left out a "}")
 
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  • #3
Since I can't see Halls' Latex image, he was saying that [tex]\int \csc^2(y)dy[/tex] is very simple, noting that what the derivative of cot(y) is.
 
  • #4
Ivy's image is: [tex]\frac{1}{sin^2y}= csc^2y[/tex]
 

FAQ: Integration of 1/x^2 sqrt(16-x) with substitution

What is the purpose of using substitution in the integration of 1/x^2 sqrt(16-x)?

Substitution is used to simplify the integrand and make it easier to solve. In this case, substituting u = 16-x will eliminate the square root and make the integral solvable using basic integration techniques.

How do you choose the appropriate substitution for this integral?

The most effective substitution for this integral is u = 16-x, as it eliminates the square root and simplifies the integrand. Generally, the best substitution is one that simplifies the integrand and makes it easier to solve.

What are the steps for solving this integral using substitution?

The steps for solving this integral are as follows:
1. Identify the appropriate substitution, in this case u = 16-x
2. Rewrite the integrand in terms of u
3. Substitute u back into the integral
4. Solve the resulting integral using basic integration techniques
5. Substitute back in the original variable, x, to get the final answer.

Is there any other method for solving this integral without using substitution?

Yes, this integral can also be solved using integration by parts. However, substitution is the more efficient and straightforward method in this case.

Can the substitution method be used for any integral?

No, substitution can only be used for certain types of integrals where the substitution simplifies the integrand. For example, it would not be effective for integrals involving trigonometric functions.

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