- #1
PhyStan7
- 18
- 0
Hi all, I am having a problem with an integration.
Solve the integration 3/(1+4x)^0.5 between x=0 and x=2. Basically find the area under a curve of the equation between x=0 and x=2.
I know the answer is 3 but can't get to it. I tried rewriting it as 3(1+4x)^-0.5 and solving bu got stupid answers like 15. and 21 to lots of dp. I can't find the mark scheme to the past paper i am doing anywhere on the internet so can't find a solution. Help would be much appreciared, thanks
Solve the integration 3/(1+4x)^0.5 between x=0 and x=2. Basically find the area under a curve of the equation between x=0 and x=2.
I know the answer is 3 but can't get to it. I tried rewriting it as 3(1+4x)^-0.5 and solving bu got stupid answers like 15. and 21 to lots of dp. I can't find the mark scheme to the past paper i am doing anywhere on the internet so can't find a solution. Help would be much appreciared, thanks