- #1
mickellowery
- 69
- 0
Homework Statement
[tex]\int[/tex][tex]\frac{e^xcos(log_7(e^x+9))}{(e^x+9)ln(7)}[/tex]dx
Homework Equations
The Attempt at a Solution
Let u= (ex+9)
du= exdx
New integral [tex]\int[/tex][tex]\frac{cos(log_7(u))}{(u)ln(7)}[/tex]du
This is where I got l little lost. Should I let log7(u)=[tex]\frac{ln(u)}{ln(7)}[/tex]? Or is this just a waste of time. I was thinking after that I would use log rules to make it ln(u)-ln(7) and then split it into two separate integrals and follow that by partial fractions. I'm just curious if I'm on the right track.