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sg001
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Homework Statement
find ∫x/√(x+1).dx with limits 1 & 0
using substitution x = u^2 -1
Homework Equations
The Attempt at a Solution
dx = du
x = u^2 -1
u = √( x+1)
sub limits of 1 & 0 into u.
Hence new limits of √2 & 1
Therefore,
∫ u^2 -1/ u
= ∫ u - 1/u
= 1/2 (u)^2 - ln u
Plugging in limits of √2& 1
(1/2 * 2 - ln √ 2 ) - (1/2)
= ( 1/2 - 1/2 ln (2))
Cant work out where I have stumbled, any ideas?