Intensity of Cu K-alpha radiation (excitation voltage)

[sh1t8ra1n]

Hello there folks, I have some materials science HW I would like some help with. I need to find the intensity of Kα radiation based on the equation:
I_Kα = Bi(V_A - V_K)^1.5, where B is a machine dependent parameter, i is the tube current, V_A is applied voltage, V_K is excitation voltage. Also included in the problem is the fact that at 30kV applied voltage, the intensity is 90 times above the continuous spectrum. I need to determine the intensity at 50kV operating voltage. I have the binding energies of the Cu orbitals, but I do not know how to turn those into excitation voltage, and I do not know how to calculate the tube current, I assume you can find it from the operating voltage...?

Thanks for any suggestions or tips!

 

[Navin A S]

The calculation of tube current can be determined from the operating voltage and the power rating of the X-ray tube. You need to know the power rating of the X-ray tube to calculate the tube current. The excitation voltage can be determined from the binding energies of the Cu orbitals. The energy of the X-ray photons is equal to the difference between the binding energy of the electron orbital and the excitation voltage. Once you have calculated the tube current and excitation voltage, you can plug them into the equation and determine the intensity of the Kα radiation at 50kV operating voltage.