- #1
atay5510
- 10
- 0
Hi,
I am aware that due to the three body kinematics of beta decay, the energy spectrum of the electrons emitted is a continuous spectrum (where at one extreme the electron gets all of the disintegration energy and the antineutrino none, and the converse at the other extreme)
I am doing an experiment at university to measure the electron energy spectrum of Bi-207, and there are a number of spikes in electron spectrum
.
How is it that Bi-207 can generate electrons of well-defined energy? Bi-207 decays by electron capture to Pb-207, so I guess this isn't really a beta decay question at all.
I know the answer to the question involves internal electron conversion. But which element undergoes internal conversion? Is the Pb-207 nuclei created in an excited state and it becomes stable by emitting electrons of distinct energies through internal conversion?
Thanks :)
I am aware that due to the three body kinematics of beta decay, the energy spectrum of the electrons emitted is a continuous spectrum (where at one extreme the electron gets all of the disintegration energy and the antineutrino none, and the converse at the other extreme)
I am doing an experiment at university to measure the electron energy spectrum of Bi-207, and there are a number of spikes in electron spectrum
.
How is it that Bi-207 can generate electrons of well-defined energy? Bi-207 decays by electron capture to Pb-207, so I guess this isn't really a beta decay question at all.
I know the answer to the question involves internal electron conversion. But which element undergoes internal conversion? Is the Pb-207 nuclei created in an excited state and it becomes stable by emitting electrons of distinct energies through internal conversion?
Thanks :)