Intersection of Sets Homework: Nonemptiness?

In summary, the question is whether the intersection of a sequence of subsets of real numbers, each satisfying a certain condition, is nonempty. For the first part, a counterexample can be constructed by considering a sequence that converges to the empty set. However, for the second part, where the subsets are closed intervals, the answer is yes since the intersection of any finite collection of closed intervals is always nonempty.
  • #1
levicivita
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Homework Statement



let [itex]A_{1}, A_{2}, ...[/itex] be a sequence of subsets of R such that the intersection of the [itex]A_{1}, A_{2}, A_{3}..., A_{n} [/itex] is nonempty for each n greater than/equal to 1. Does it follow that the intersection of all [itex]A_{n}[/itex]'s is nonempty?
Does the answer change if you are given the extra information that each [itex]A_{n}[/itex] is a closed interval, that is a set of the form [itex][a_{n}, b_{n}] = {x member of R : a_{n} \leg x \leq b_{n}[/itex] for some pair of real numbers [itex](a_{n},b_{n})[/itex] with [itex]a_{n} < b_{n}[/itex]

Homework Equations





The Attempt at a Solution


I don't really have a clue how to start this. It seems to me that in both cases it should be non empty, but I'm really not sure. I'm not looking for some one to do this for me, because I want to be able to do it myself - I would appreciate it if someone could point me in the right direction without giving the game away.
 
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  • #2
For the first one, try to think of a counterexample. Perhaps try it for some sequence that converges to the empty set.

For the second part, you have a sequence of closed intervals such that the intersection of some finite collection of sets (in the sequence) is non empty. So what can you say about the intervals (think of them visually)?
 

FAQ: Intersection of Sets Homework: Nonemptiness?

What is the definition of "nonemptiness" in the context of sets?

In the context of sets, "nonemptiness" refers to the property of a set containing at least one element. This means that the set is not empty or has no elements.

How do you determine if the intersection of two sets is nonempty?

To determine if the intersection of two sets is nonempty, you need to check if there are any elements that are common to both sets. If there is at least one common element, then the intersection is nonempty. If there are no common elements, then the intersection is empty.

Can the intersection of two empty sets be nonempty?

No, the intersection of two empty sets is always empty. This is because by definition, an empty set has no elements, so there can be no common elements between two empty sets.

How do you prove that the intersection of two sets is nonempty?

To prove that the intersection of two sets is nonempty, you need to find at least one element that is common to both sets. This can be done by listing out the elements in each set and finding any elements that are the same in both sets. Alternatively, you can use set notation and logical reasoning to show that the intersection is nonempty.

What is the significance of the concept of nonemptiness in set theory?

The concept of nonemptiness is important in set theory because it helps to determine the relationships between sets. If the intersection of two sets is nonempty, it means that there is at least one element that is common to both sets, which can provide valuable information for further analysis and calculations. Additionally, the concept of nonemptiness is closely related to the concept of subsets and can help to prove or disprove certain statements in set theory.

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