- #1
Soccer
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HOMEWORK SUBMITTED IN WRONG FORUM, SO NO TEMPLATE
I uploaded an image of the problem, it seems to be fairly straight forward. However, my textbook indicates the answer as being 6 m/s, I am consistently getting 3 m/s. Any help would be appreciated!
Because there is no air resistance, the horizontal velocity is constant.
2ax+vo^2=vf^2
We can set the Vo equal to zero, find the required speed to achieve .45m vertically.
We find Viy=2.97m/s
vf=at
2.97=at
2.97/9.81=.3 seconds
Horizontal speed (distance over time)- constant speed
.25/.3=.833 m/s
(.833^2+2.97^2)^.5=3m/s
I know that the height and length indicated in the problem yield a angle of 61 degrees, however, this information still does not yield the correct answer.
I uploaded an image of the problem, it seems to be fairly straight forward. However, my textbook indicates the answer as being 6 m/s, I am consistently getting 3 m/s. Any help would be appreciated!
Because there is no air resistance, the horizontal velocity is constant.
2ax+vo^2=vf^2
We can set the Vo equal to zero, find the required speed to achieve .45m vertically.
We find Viy=2.97m/s
vf=at
2.97=at
2.97/9.81=.3 seconds
Horizontal speed (distance over time)- constant speed
.25/.3=.833 m/s
(.833^2+2.97^2)^.5=3m/s
I know that the height and length indicated in the problem yield a angle of 61 degrees, however, this information still does not yield the correct answer.