- #1
nontradstuden
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Hello. Am I counting right with these problems? I can't remember exactly how they were worded, but I remember what they were asking...
1) Given 20 men and 20 women, how many groups of 12 can you make with 6 men and 6 women.
I said 20.Combination.6 * 20.Combination.6.
2) given S= {1, 2, 4, 5, 7}, you will choose 3 randomly from the set. What's the probability of getting an even number greater than 500?
I said 12 / 5.Permutation.3.
How I got 12:
1. 3 ways of having 5 first, 2 last.
2. 3 ways of having 5 first, 4 last.
3. 3 ways of having 7 first, 2 last.
4. 3 ways of having 7 first, 4 last.
Added it up to get 12. I then divided it by a permutation because order is important?...
3) What is the probability that two randomly chosen people were both not born in June?
I said P(First not born in June ^ Second not born in June)= (11/12) * (11/12)
Is my counting right? Thanks for your help.
1) Given 20 men and 20 women, how many groups of 12 can you make with 6 men and 6 women.
I said 20.Combination.6 * 20.Combination.6.
2) given S= {1, 2, 4, 5, 7}, you will choose 3 randomly from the set. What's the probability of getting an even number greater than 500?
I said 12 / 5.Permutation.3.
How I got 12:
1. 3 ways of having 5 first, 2 last.
2. 3 ways of having 5 first, 4 last.
3. 3 ways of having 7 first, 2 last.
4. 3 ways of having 7 first, 4 last.
Added it up to get 12. I then divided it by a permutation because order is important?...
3) What is the probability that two randomly chosen people were both not born in June?
I said P(First not born in June ^ Second not born in June)= (11/12) * (11/12)
Is my counting right? Thanks for your help.