Intro to Quantum Mechanics - Formalism normalisation

In summary, the conversation discusses the use of i/sqrt(2) for normalizing c1 and why it is a complex number. It is revealed that the relationship c1 = ic0 is necessary for solving the problem and that the exponential can also be interpreted as i.
  • #1
Graham87
72
16
Homework Statement
See pic
Relevant Equations
See pic
I can't figure out how they get i/sqrt(2) for normalisation of c1. Why is it a complex number? If I normalise c1 I just get 1/sqrt(2) because i disappears in the absolute value squared.

Thanks

1.png
 
Physics news on Phys.org
  • #2
It looks like you left out other information from the problem, but apparently, there was the relation ##c_1 = i c_0##. That's where the ##i## comes from. Note that you had to have this relationship to solve for ##c_0##
otherwise you'd have two unknowns but only one equation.
 
  • Like
Likes topsquark and Graham87
  • #3
vela said:
It looks like you left out other information from the problem, but apparently, there was the relation ##c_1 = i c_0##. That's where the ##i## comes from. Note that you had to have this relationship to solve for ##c_0##
otherwise you'd have two unknowns but only one equation.

There was this relation:

1.png


Aha, so the exponential is also interpreted as i then. Thanks, got it!
 
  • #4
##e^{i\pi/2}= \cos (\pi/2) + i \sin(\pi/2) = i##
##e^{iv}= \cos (v) + i \sin(v) ##
 
  • Like
Likes SammyS, topsquark and Graham87

Similar threads

Replies
22
Views
2K
Replies
10
Views
871
Replies
6
Views
2K
Replies
1
Views
6K
Replies
11
Views
2K
Back
Top