- #1
leonj
- 1
- 0
I am trying to simulate and animate inverse dynamics. So I need to calculate torques. I started out by just taking a rod which rotates about its COM, applied a torque and then just used [itex]\tau=I\alpha[/itex] to make sure I get back the same torque I applied. Next, I attached the rod to the ground with a hinge joint. This time to get the torque I used the parallel axis theorem to get [itex]\tau=(I_{COM}+Mh^2)\alpha[/itex]. So my next step is to attach a second rod to the end of the one attached to the ground. What I am stuck on now is I am not sure how the two rods interact.
For example how do I calculate the torque on the rod connected to the ground? When it is just one rod I used the aforementioned [itex]\tau=(I_{COM}+Mh^2)\alpha[/itex], but now with the other rod attached to it, what else do I need to take into account? Is there a negative torque on the opposite side?
Note: For now I have disabled gravity.
I would appreciate any insight. Thanks
For example how do I calculate the torque on the rod connected to the ground? When it is just one rod I used the aforementioned [itex]\tau=(I_{COM}+Mh^2)\alpha[/itex], but now with the other rod attached to it, what else do I need to take into account? Is there a negative torque on the opposite side?
Note: For now I have disabled gravity.
I would appreciate any insight. Thanks