- #1
jaysquestions
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Is this normal? it doesn't seem correct.
The equation for the portion of circle with radius 1 unit in the 1st Quadrant is:
## y = f(x) = \sqrt{1-x^2} ## Domain is 0<x
But when I calculate f'(x) I also get
## f'(x) = \sqrt{1-x^2} ##
I thought inverse functions always reflect about y=x. Please help...confused...thanks
The equation for the portion of circle with radius 1 unit in the 1st Quadrant is:
## y = f(x) = \sqrt{1-x^2} ## Domain is 0<x
But when I calculate f'(x) I also get
## f'(x) = \sqrt{1-x^2} ##
I thought inverse functions always reflect about y=x. Please help...confused...thanks