- #1
redq
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So, in integrals that lead to inverse hyperbolics and can be solved with trigonometric substitution i just get lost. I know how to use both of them but i don't know which to use.
For the sake of simplicity i'll just go with this one
∫ dx/sqrt(4+x^2)
We know this equals arcsinh(x/2) ,right?
or we can just write x=2tant and find a completely different answer?
Which one of these solutions are "more true" , assuming you are in the final exam?
Or just they aren't true and I'm missing something?
For the sake of simplicity i'll just go with this one
∫ dx/sqrt(4+x^2)
We know this equals arcsinh(x/2) ,right?
or we can just write x=2tant and find a completely different answer?
Which one of these solutions are "more true" , assuming you are in the final exam?
Or just they aren't true and I'm missing something?