- #1
_diego
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Hi, this is my first post, and I'm not sure if I'm posting this in the right place.
I have a 2nd order diff. equation:
3y''(t) + 2y'(t) + 5y(t) = 3
with initial values: y'(0) = 1, y(0) = 0
After using Laplace transform I get:
Y(s) = (3 + 3s) / (s*[3s2 +2s +5])
I believe it is correct, but even if it's not, what I'm interested in is how to solve this particular inverse laplace transform where I can't use partial fractions due to 3s2 +2s +5 not having any roots.
I'm kind of stuck here, but maybe I could split the fraction like:
Y(s) = 3 / (s*[3s2 +2s +5]) + 3 / ([3s2 +2s +5])
but the problem would remain.
Thanks
Homework Statement
I have a 2nd order diff. equation:
3y''(t) + 2y'(t) + 5y(t) = 3
with initial values: y'(0) = 1, y(0) = 0
Homework Equations
After using Laplace transform I get:
Y(s) = (3 + 3s) / (s*[3s2 +2s +5])
I believe it is correct, but even if it's not, what I'm interested in is how to solve this particular inverse laplace transform where I can't use partial fractions due to 3s2 +2s +5 not having any roots.
The Attempt at a Solution
I'm kind of stuck here, but maybe I could split the fraction like:
Y(s) = 3 / (s*[3s2 +2s +5]) + 3 / ([3s2 +2s +5])
but the problem would remain.
Thanks