Invertible, kernel, and range of a Linear Transformation

In summary, we discussed various topics related to linear transformations and their properties, including invertibility, basis for range, and isomorphism. We also looked at the rank-nullity theorem and the concept of a linear map or transformation. We also discussed how to prove that a linear transformation is onto if it is one-to-one. Finally, we explored the idea that the dimension of a subspace is equal to the dimension of the whole space when they are equal, and discussed how this can help us prove certain statements about linear transformations.
  • #1
hkus10
50
0
1) Let L:R3 >>>R3 be defined by
L([1 0 0]) = [1 2 3],
L([0 1 0]) = [0 1 1],
L([0 0 1]) = [1 1 0]

How to prove that L is invertible? I have the idea of one-to-one and onto, but I do not know how to apply them to this proof.

2) Find a linear transformation L:R2 >>>R3 such that {[1 -1 2], [3 1 -1]} is a basis for range (L). How can I approach this problem?

3) Let S = {v1,…,vn} be an ordered basis for vector space V . Let
L :V →R^n be given by L(v) = [v]S . Prove that L is an
isomorphism( prove that the linear transformation is one-to-one and onto)
What I know so far is that {[v1]s, [v2]s,...,[vn]s} is an ordered basis for R^n and v can be written in a unique way sych that v = a1v1+...+anvn = 0.
How can I go from there?

4) If L:V>>>W is a linear transformation of a vector space V into a vector space W and dim V = dim W, then prove that if L is one-to-one, then it is onto.
I get a point that dim(W) = dim(range(L)). What I am trying to get to is W = range(L). Then, by definition, L is onto. My question is that how can I prove that dim(W) = dim(range(L)) >>> W = range(L) and by what Thm of defin? If not, how should I approach this question?

5) Let L:R^n>>>R^m be a linear transformation defined by L(x) = Ax, for x in R^n. Then, L is onto if and only if rank A = m.
In this question, is the nullity of A equal to the nullity of L?

Thanks
 
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  • #2
1)
What is L's matrix representation with respect to the standard basis? If you can show that matrix representation to be invertible, then L is also invertible.

2)
Look up the rank-nullity theorem.

3)
Choose some basis for [tex]R^2[/tex], then define a map from that basis to the desired basis for the image. The action of a linear map on a basis uniquely defines that linear map, so you're done.

4)
I'm not totally sure I follow the question. But I think you've been asked to show that if L is defined as mapping vectors v to the coordinates of their representation in a basis S, then L is an isomorphism.

From what you have, if [tex]\{ [v_1]_s, ..., [v_n]_s \}[/tex] is a basis for [tex]R^n[/tex], what does that tell you about the image of L?

Good luck with your work!
 
  • #3
upsidedowntop said:
2)
Look up the rank-nullity theorem.

3)
Choose some basis for [tex]R^2[/tex], then define a map from that basis to the desired basis for the image. The action of a linear map on a basis uniquely defines that linear map, so you're done.

For 2) Is the answer just simply 2 + 5?

For 3) what do you mean by a linear map?

Also, I have an additional question which is If L:V>>>W is a linear transformation of a vector space V into a vector space W and dim V = dim W, then prove that if L is one-to-one, then it is onto.
I get a point that dim(W) = dim(range(L)). What I am trying to get to is W = range(L). Then, by definition, L is onto. W = range(L). My question is that how can I prove that dim(W) = dim(range(L)) >>> W = range(L) and by what Thm of defin? If not, how should I approach this question?
 
  • #4
hkus10 said:
For 2) Is the answer just simply 2 + 5?

For 3) what do you mean by a linear map?

Also, I have an additional question which is If L:V>>>W is a linear transformation of a vector space V into a vector space W and dim V = dim W, then prove that if L is one-to-one, then it is onto.
I get a point that dim(W) = dim(range(L)). What I am trying to get to is W = range(L). Then, by definition, L is onto. W = range(L). My question is that how can I prove that dim(W) = dim(range(L)) >>> W = range(L) and by what Thm of defin? If not, how should I approach this question?

2) Yes. It's an easy question assuming rank-nullity.

3) Linear map and linear transformation are synonymous. If one runs into mathematical terminology one does not recognize, reading the first paragraph of the wikipedia page for the term will usually sort out one's difficulty. For example, linear map and linear transformation both send you to the same wikipedia page that begins with
""""
In mathematics, a linear map, linear mapping, linear transformation, or linear operator (in some contexts also called linear function) is a function between two vector spaces that preserves the operations of vector addition and scalar multiplication. The expression "linear operator" is commonly used for linear maps from a vector space to itself (i.e., endomorphisms).
"""

The implication you suggest proving for the last question is true. It might be easier to prove the following more general statement though.
Let V be a finite dimensional vector space with vector subspace W. Then dim(W) = dim(V) implies W = V.
 
  • #5
push!
 

FAQ: Invertible, kernel, and range of a Linear Transformation

What is an invertible linear transformation?

An invertible linear transformation is a linear transformation that has a unique inverse function, meaning that the transformation can be undone. This means that for every output, there is only one corresponding input, and vice versa.

What does it mean for a linear transformation to have an invertible kernel?

A linear transformation with an invertible kernel means that the only vector that gets mapped to the zero vector is the zero vector itself. This means that the transformation does not lose any information, as every input vector has a unique output vector.

How is the invertible kernel related to the invertible range of a linear transformation?

The invertible kernel and the invertible range are two properties of a linear transformation that are closely related. If a transformation has an invertible kernel, it means that the transformation does not lose any information. Similarly, if a transformation has an invertible range, it means that the transformation does not map any two different input vectors to the same output vector.

What is the relationship between the invertible kernel and the rank of a linear transformation?

The invertible kernel and the rank of a linear transformation are inversely related. The rank of a linear transformation is the number of linearly independent columns in the transformation's matrix representation. If the rank of a transformation is equal to its dimension, then the transformation has an invertible kernel.

Can a linear transformation have an invertible kernel and a non-invertible range?

No, a linear transformation cannot have an invertible kernel and a non-invertible range. This is because the invertible kernel ensures that the transformation does not lose any information, while the non-invertible range means that the transformation maps some input vectors to the same output vector, thus losing information.

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