- #1
Ad123q
- 19
- 0
I have in my notes that (2X,5) is an ideal of Z[X], but I can't see why this can be so.
For example 5+2X is in (2X,5) and 7+X is in Z[X] but then
(5+2X)(7+X) =
= 35+5X+14X+2X^2
= 2X^2+19X+35.
19 is not divisible by 2 and so this element is not in (2X,5), contradicting the "absorbance" property of ideals.
For example 5+2X is in (2X,5) and 7+X is in Z[X] but then
(5+2X)(7+X) =
= 35+5X+14X+2X^2
= 2X^2+19X+35.
19 is not divisible by 2 and so this element is not in (2X,5), contradicting the "absorbance" property of ideals.