- #1
dirtypurp
- 8
- 1
Let f : N −→ R and f(x) = √ 9x
The domain is all natural numbers: {0, 1, 2, 3, ...}
The codomain is all real numbers.
The range i believe is [0, +infinity)
I believe that although the above is a function since every input of x provides a output that fits in our codomain. I also believe that this is a injective function (one to one correspondence) since f(x)=f(y); x=y. However I do not believe that it is a bijection since not every output we get, which is considered to be our range, is equal to the codomain which is all real numbers. For example no negative output can be given.
Does anyone care to agree or disagree?
The domain is all natural numbers: {0, 1, 2, 3, ...}
The codomain is all real numbers.
The range i believe is [0, +infinity)
I believe that although the above is a function since every input of x provides a output that fits in our codomain. I also believe that this is a injective function (one to one correspondence) since f(x)=f(y); x=y. However I do not believe that it is a bijection since not every output we get, which is considered to be our range, is equal to the codomain which is all real numbers. For example no negative output can be given.
Does anyone care to agree or disagree?