- #1
sunjin09
- 312
- 0
If the subring S of a ring R has a unit element e' but R does not have a unit element then e' must be a divisor of zero.
I was able to show that if R has a unit element e≠e', then (e-e')e'=0, where e-e'≠0, implying e' is a divisor of zero, but if R does not have a unit element I can't see why, please help, thank you.
I was able to show that if R has a unit element e≠e', then (e-e')e'=0, where e-e'≠0, implying e' is a divisor of zero, but if R does not have a unit element I can't see why, please help, thank you.