knowLittle said:Homework Statement
-arctan(x/y) = arctan(y/x) ?
Are they equivalent? I can't find anything online and I have seen that my solution to some problem involves
-arctan(x/y) and it agrees with Wolfram Alpha. On the other hand, my professor's solution shows the arctan(y/x) and this is why I am doubtful.
Any ideas?
Thank you.
The equation -arctan(x/y) = arctan(y/x) is used to find the value of the angle between two lines or vectors in a two-dimensional coordinate system.
To solve this equation, you will need to use the inverse tangent function (arctan) on both sides. This will give you the values of x and y, which can then be used to find the angle between the two lines or vectors.
There are no specific restrictions for x and y in this equation. However, the equation is only valid when both x and y are non-zero values.
The equation -arctan(x/y) = arctan(y/x) is a trigonometric identity. It is derived from the tangent angle addition formula: tan(A + B) = (tan A + tan B)/(1 - tan A * tan B). When A = arctan(x/y) and B = arctan(y/x), the equation becomes -arctan(x/y) = arctan(y/x).
The equation -arctan(x/y) = arctan(y/x) has various practical applications in fields such as engineering, physics, and mathematics. It is used to calculate angles in right triangles, determine the direction of a vector, and solve problems involving motion and forces. It is also used in navigation and geodesy to determine distances and angles between points on a curved surface.