- #1
Yankel
- 395
- 0
Hello all,
If A and B are both squared invertible matrices and A is also symmetric and:
\[AB^{-1}AA^{T}=I\]
Can I say that
\[B=A^{3}\] ?
In every iteration of the solution, I have multiplied both sides by a different matrix. At first by the inverse of A, then the inverse of the transpose, etc...Is this the correct approach to solve this ? Thank you in advance !
Another question. If A in both symmetric and invertible, it doesn't mean that the inverse of A is equal to A, right ?
If A and B are both squared invertible matrices and A is also symmetric and:
\[AB^{-1}AA^{T}=I\]
Can I say that
\[B=A^{3}\] ?
In every iteration of the solution, I have multiplied both sides by a different matrix. At first by the inverse of A, then the inverse of the transpose, etc...Is this the correct approach to solve this ? Thank you in advance !
Another question. If A in both symmetric and invertible, it doesn't mean that the inverse of A is equal to A, right ?