Is Bohmian Mechanics Compatible with Polarisation Experiments?

[StevieTNZ]

I was thinking: if you send light through a 45 degree filter (D filter), and then sent that light through another D filter, because it is now in superposition of V+H state, and according to 'Beyond Measure', light in that state (left circularly polarised) would go through the 2nd filter 100% of the time.

But according to Bohm mechanics, the light be in a definite verticle or horizontal polarisation (even after going through the first D filter, thereby meaning that if it hit the 2nd D polariser, only half would go through, as expected if it were in a V or H polariser state (according to us, we expect it to be in a superposition, but its actually in a definite state).

Now, Ken G responded and said things about additional instructions about what to do if the photon encounters filters in particular orders.

But I see no difference in a photon with instructions and a V polarisation, and a photon with just a V polarisation. Both are the same physical realities, and the 'instructed photon' should behave just like a V polarised photon, only go through half the time if it encounters a 2nd D filter.

 

[Demystifier]

But according to Bohm mechanics, the light be in a definite verticle or horizontal polarisation ...

No, this is not so according to Bohm mechanics. See e.g.
http://xxx.lanl.gov/abs/quant-ph/9601013
especially Sec. 4.

 

[StevieTNZ]

No, this is not so according to Bohm mechanics. See e.g.
http://xxx.lanl.gov/abs/quant-ph/9601013
especially Sec. 4.

Now I'm being told two different things: you say no, but two other Physics Professors tell me all physical properties of a quantum system have definite states at all times.

 

[Demystifier]

Now I'm being told two different things: you say no, but two other Physics Professors tell me all physical properties of a quantum system have definite states at all times.

I don't know who they are, but they are obviously not experts in Bohmian mechanics.