Is Charge Density Only Defined for Stationary Charges?

In summary, charge density is defined for both stationary and moving charges. In the presence of moving charge, the equations for potential and electric field are modified to take into account the current. However, for most practical purposes and in the Coulomb gauge, the equations still hold true. A current can occur with a zero charge density, but the density of negative charges will still equal that of the positive charges in the material. This can be visualized through the example of a hall with men and women, where the density remains the same but there could be a charge buildup if the men walk at different rates.
  • #1
CrusaderSean
44
0
silly question i guess, but is charge density defined only for stationary charges?

i'm asking this because I did a couple homework problems on finding electric field in linear dielectric material. Dielectric is between two surfaces held at constant potential difference (ie. parallel plate, concentric sphere or cylinder.. well neglect fringe effects). From what I understand, there is no charge (free or induced) density in the dielectric material because they only occur on boundary between conductor and dielectric. So I solved the problems using Laplace's equation (instead of Poisson). I found there is constant current going through the dielectric material. Since current is flux of charges, there must be charges moving through dielectric. Those charges aren't in the charge density definition because they're acting as current or some other reason? Perhaps I'm confusing some issues here...
 
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  • #2
[itex]\rho_{el}\left(\vec{r},t\right) [/itex] describes the volumic density of electric charge at the point [itex] \vec{r} [/itex] at the moment "t",no matter if the charge is moving or not...

Daniel.
 
  • #3
my class is only on electrostatics.. so the [tex]\rho[/tex] in the equations below are static charges only?
[tex]\nabla{^2} \cdot V = \frac{-\rho}{\epsilon}[/tex]
[tex]\nabla \cdot E = \frac{\rho}{\epsilon}[/tex]
 
  • #4
Yeah.Electrostatics means static fields created,obviously by time independent electric charge densities.

Daniel.
 
  • #5
CrusaderSean said:
my class is only on electrostatics.. so the [tex]\rho[/tex] in the equations below are static charges only?
[tex]\nabla{^2} \cdot V = \frac{-\rho}{\epsilon}[/tex]
[tex]\nabla \cdot E = \frac{\rho}{\epsilon}[/tex]

Those equations apply to moving charges as well. Both of them are equivalent to one of Maxwell's Equations. In the presence of moving charge, however, that won't be enough to determine the electric field at a given point because it will have a non-zero curl.
 
  • #6
Nope,for moving charges (in vacuum) we have

[tex] \square V\left(\vec{r},t\right)=-\frac{\rho\left(\vec{r},t\right)}{\epsilon_{0}} [/tex]

Daniel.
 
  • #7
SpaceTiger said:
Those equations apply to moving charges as well. Both of them are equivalent to one of Maxwell's Equations...

i thought those equations were general (for static and dynamic) as well... guess i was wrong.
 
  • #8
Gauss's law is the same (in mathematical form,not as functional dependence of the quantities involved) both for static & dynamic description.

The potential's equation is diff,however...Poisson vs.d'Alembert...

Daniel.
 
  • #9
CrusaderSean said:
i thought those equations were general (for static and dynamic) as well... guess i was wrong.

You only need worry yourself about such things if your charges are moving relativistically, but dexter's equation is more general.
 
  • #10
That potential equation i posted is valid in the Coulomb gauge.Typically relativistic...

Daniel.
 
  • #11
An electric current can occcur with a zero charge density.
The current usually consists of negative electrons moving through the material,
while the positive charges remain fixed.
The density of negative charges equals that of the positive charges in the material.
Think of a hall with 100 men and 100 women in it. If the men start walking, but the women remain standing. The density of people will remain the same, but men will pile u at one end of the hall. There could be a charge buildup if the men walk at different rates. That would be described by the continutity eqation.
 

FAQ: Is Charge Density Only Defined for Stationary Charges?

What is the definition of charge density?

Charge density refers to the amount of electric charge per unit volume of a material or system. It is typically represented by the symbol ρ and is measured in units of coulombs per cubic meter (C/m³).

How is charge density calculated?

Charge density can be calculated by dividing the total electric charge by the volume of the material or system. For example, if a material has a total charge of 10 coulombs and a volume of 5 cubic meters, the charge density would be 10/5 = 2 C/m³.

What is the difference between linear and volumetric charge density?

Linear charge density refers to the amount of electric charge per unit length of a one-dimensional object, such as a wire. It is measured in units of coulombs per meter (C/m). Volumetric charge density, on the other hand, refers to the amount of charge per unit volume of a three-dimensional object or material.

How does charge density affect electric fields?

Charge density plays a crucial role in determining the strength and direction of electric fields. Higher charge densities result in stronger electric fields, while lower charge densities result in weaker electric fields. Additionally, the distribution of charge within a material or system can also affect the shape and direction of electric fields.

Can charge density be negative?

Yes, charge density can be negative. This typically occurs when the material or system has a net negative charge, meaning it has an excess of electrons. In this case, the charge density would be represented by a negative value, indicating an overall negative charge per unit volume.

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