- #1
Owen Holden
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If classical logic is inconsistent then so is classical mathematics.
A. x=y -> (Fx <-> Fy). This is an axiom of first order logic and it is a theorem of second order logic. (Leibnitz's Law)
A is a theorem of Principia Mathematica, *13.15.
1. x=y -> ([](x=x) <-> [](x=y)).
therefore,
2. x=y -> [](x=y)?? (Because [](x=x) is an axiom or a theorem)
3. Herkyl=Herkyl -> [](Herkyl=Herkyl) ??
Surely it is true that Herkyl is self identical, but, it is false to say that Herkyl=Herkyl is logically true.
B. y=(the x:Gx) -> (Fy <-> F(the x:Gx)).
B is a theorem of Principia Mathematica *14.15.
1a. (the x:Gx)=y -> ([](y=y) <-> []((the x:Gx)=y).
2a. (the x:Gx)=y -> []((the x:Gx)=y)??
3a. (the number of planets)=9 -> []((the number of planets)=9)??
It is clearly false to say that (Herkyl=Herkyl) is necessarily true, and,
It is clearly false to say that (the number of planets)=9, is necessarily true.
That is to say the logical deductions, 3 and 3a, are false.
Therefore classical logic is inconsistent!
A. x=y -> (Fx <-> Fy). This is an axiom of first order logic and it is a theorem of second order logic. (Leibnitz's Law)
A is a theorem of Principia Mathematica, *13.15.
1. x=y -> ([](x=x) <-> [](x=y)).
therefore,
2. x=y -> [](x=y)?? (Because [](x=x) is an axiom or a theorem)
3. Herkyl=Herkyl -> [](Herkyl=Herkyl) ??
Surely it is true that Herkyl is self identical, but, it is false to say that Herkyl=Herkyl is logically true.
B. y=(the x:Gx) -> (Fy <-> F(the x:Gx)).
B is a theorem of Principia Mathematica *14.15.
1a. (the x:Gx)=y -> ([](y=y) <-> []((the x:Gx)=y).
2a. (the x:Gx)=y -> []((the x:Gx)=y)??
3a. (the number of planets)=9 -> []((the number of planets)=9)??
It is clearly false to say that (Herkyl=Herkyl) is necessarily true, and,
It is clearly false to say that (the number of planets)=9, is necessarily true.
That is to say the logical deductions, 3 and 3a, are false.
Therefore classical logic is inconsistent!
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