- #1
Jules18
- 102
- 0
My notes say the deriv. of inverse Cotangent is -1/(1+x2)
But when I plot the derivative of this function: 1/Tan-1x
against -1/(1+x2), I get two different graphs.
Is Cot-1x not the same thing as 1/Tan-1x ?
~Jules~
But when I plot the derivative of this function: 1/Tan-1x
against -1/(1+x2), I get two different graphs.
Is Cot-1x not the same thing as 1/Tan-1x ?
~Jules~