- #1
Buffu
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I read people saying that dy/dx is not a ratio because it is a limit or standard part of a ratio. $${dy\over dx} = \lim_{h \to 0} {f(x +h) - f(x) \over h}, \ \ \ {dy\over dx} = st\left( {f(x +h) - f(x) \over h}\right)$$
what I get is ##{f(x +h) - f(x) \over h}## is a ratio but putting a limit or st makes it something else than a ratio.
So my question is ##\lim_{x \to 0} \frac 4 5## a ratio ? If it is then how would you put an formal argument against dy/dx as a ratio ?
what I get is ##{f(x +h) - f(x) \over h}## is a ratio but putting a limit or st makes it something else than a ratio.
So my question is ##\lim_{x \to 0} \frac 4 5## a ratio ? If it is then how would you put an formal argument against dy/dx as a ratio ?
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