- #1
Jimmy Snyder
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I'm sorry, but the formulae pertinent to this question are too difficult for my spotty knowledge of tex. This means that the only people who can help me with this are those who have a copy of Ryder's QFT available.
My problem comes from page 58 of Ryder's QFT. I think the text is asking me to show that equation 2.180 is an example of equation 2.179 with an appropriate choice of [tex]a^\alpha[/tex].
Too complicated for me to reproduce. Please refer to the book if you have it.
Actually, I have a solution for this by differentiating the Lorentz transformation equations with respect to v and treating x as a constant. For instance:
[tex]x' = \gamma(x + vt)[/tex]
[tex]\frac{\partial}{\partial v}(x + vt)(1-v^2)^{-1/2}|(v = 0) = t(1-v^2)^{-1/2} + (x + vt)v(1-v^2)^{-3/2}|(v = 0) = t[/tex]
I just feel funny about treating x as a constant when take the derivative with respect to v. If its wrong, what direction should I go? If it's right, why is it allowed to ignore the relation between x and [tex]\dot x[/tex]?
Homework Statement
My problem comes from page 58 of Ryder's QFT. I think the text is asking me to show that equation 2.180 is an example of equation 2.179 with an appropriate choice of [tex]a^\alpha[/tex].
Homework Equations
Too complicated for me to reproduce. Please refer to the book if you have it.
The Attempt at a Solution
Actually, I have a solution for this by differentiating the Lorentz transformation equations with respect to v and treating x as a constant. For instance:
[tex]x' = \gamma(x + vt)[/tex]
[tex]\frac{\partial}{\partial v}(x + vt)(1-v^2)^{-1/2}|(v = 0) = t(1-v^2)^{-1/2} + (x + vt)v(1-v^2)^{-3/2}|(v = 0) = t[/tex]
I just feel funny about treating x as a constant when take the derivative with respect to v. If its wrong, what direction should I go? If it's right, why is it allowed to ignore the relation between x and [tex]\dot x[/tex]?
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