Is F = ∇f if DF1/Dy = DF2/Dx for F(x,y) = (ycos(x), xsin(y))?

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The discussion centers on proving that the vector function F(x,y) = (ycos(x), xsin(y)) cannot be expressed as the gradient of a scalar function f. It is established that if F is a gradient, then the mixed partial derivatives must satisfy the equality DF1/Dy = DF2/Dx. Participants note the importance of continuous partial derivatives and reference Clairaut's theorem regarding the symmetry of second derivatives. The conversation highlights the need to analyze the first partial derivatives of F to demonstrate the failure of the gradient condition. Ultimately, the conclusion is that F does not meet the necessary criteria to be a gradient of any function f.
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Homework Statement


consider a function F : R^2 \rightarrowR^2 given as F(x,y)=(F1(x,y),F2(x,y)).Show that if F=\nablaf for some function f : R^2\rightarrowR,then
(for partial derivative )
DF1/Dy=DF2/Dx
show that F(x,y)=(ycos(X),xsin(y))is not the gradient of a function


Homework Equations





The Attempt at a Solution


i don't know how to set about this question
any clue ?
 
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