- #1
theRukus
- 49
- 0
To find the intersection of two lines in R3, you set the lines equal, right?
[a,b,c] + d[e,f,g] = [h,i,j] + k[l,m,n]
Then split these into three equations,
1. a + d(e) = h + k(l)
2. b + d(f) = i + k(m)
3. c + d(g) = j + k(n)
And solve for k and d, correct?
If k and d are consistent, then these values are used to find the point of intersection.
My question is: Is this same method used in R4, with two lines of 4 dimensions?
[a,b,c] + d[e,f,g] = [h,i,j] + k[l,m,n]
Then split these into three equations,
1. a + d(e) = h + k(l)
2. b + d(f) = i + k(m)
3. c + d(g) = j + k(n)
And solve for k and d, correct?
If k and d are consistent, then these values are used to find the point of intersection.
My question is: Is this same method used in R4, with two lines of 4 dimensions?