Is \(\frac{ax^n}{n+1} + C\) the Correct Integral of \(y=ax^n\)?

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In summary, the integral of ax^n is given by the formula (ax^(n+1))/(n+1) + C. The process for finding the integral involves using the power rule and adding the constant of integration. The integral can be simplified by following the integration process and simplifying the final answer. There are special cases for n = -1 and n = -1/2, and there are other methods for finding the integral such as u-substitution or integration by parts. These methods may be used depending on the complexity of the integral.
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tmt1
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Hi,

When integrating this function $y=a x^n $

the answer is \(\displaystyle \frac{ax^n}{n+1} + C\) , correct?

Thank you,

Tim
 
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tmt said:
Hi,

When integrating this function, "y=ax^n"

the answer is "(ax^n)/(n+1) + C", correct?

Thank you,

Tim
Hello,
The correct answer is \(\displaystyle \frac{ax^{n+1}}{n+1}+c\) can you see WHY?
I asume that we integrate respect to x!

Regards,
\(\displaystyle |\pi\rangle\)
 
  • #3
Excellent, thank you!
 

FAQ: Is \(\frac{ax^n}{n+1} + C\) the Correct Integral of \(y=ax^n\)?

What is the formula for the integral of ax^n?

The formula for the integral of ax^n is ∫ax^n dx = a/(n+1)x^(n+1) + C, where C is the constant of integration.

What is the power rule for integration?

The power rule for integration states that the integral of x^n dx is equal to x^(n+1) / (n+1) + C.

How do you solve a definite integral with ax^n?

To solve a definite integral with ax^n, you can use the formula ∫ax^n dx = a/(n+1)x^(n+1) + C and substitute the limits of integration into the equation. Then, subtract the value of the integral at the lower limit from the value of the integral at the upper limit to get the final result.

Can the integral of ax^n be solved using substitution?

Yes, the integral of ax^n can be solved using substitution. However, it is important to choose the substitution carefully in order to simplify the integral and make it easier to solve.

What is the relationship between the derivative and integral of ax^n?

The derivative of ax^n is equal to a*n*x^(n-1), while the integral of ax^n is equal to a/(n+1)x^(n+1) + C. Therefore, the integral of ax^n is the antiderivative of the derivative of ax^n.

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