- #1
Kanchana
- 3
- 0
Let H be a normal subgroup of G. Then factor group G/H is an abelian subgroup.
For x, y not in H
xHyH=yHxH
and xyH=yxH
(xyH)(yxH)^{-1}=id
xyx^{-1}y^{-1}=id
Are these steps correct?
thnx
For x, y not in H
xHyH=yHxH
and xyH=yxH
(xyH)(yxH)^{-1}=id
xyx^{-1}y^{-1}=id
Are these steps correct?
thnx