- #1
FOIWATER
Gold Member
- 434
- 12
I actually have solved the problem and received the answers that the book provided.
However I am second guessing what I did,
This is the problem:
let rho v be 10/r^2 mC/m^3 between 1<r<4
let rho v be zero elsewhere
a)find the net flux crossing the surface at r=2 m, r= 6m
b)determine D at r=1, r=5
a) I have no issues with, I can simply say that the Flux crossing the surface equals the charge enclosed and solve for the charge enclosed by integrating the volume charge density over the volume. I used triple integration in spherical coordinates with r from 1 to 2, theta from 0 to pi, and phi from 0 to 2pi. I got 40pi mC
Same goes for r=6m, I just integrated the same except r went from 1 to 4 (since there is no more charge after r = 4, or rather, the charge density was given as zero) (but the flux will remain the same at 6m as it was at 4m) 120pi
My issue is with what I did in b), applying gauss' law.
I know gauss' law holds, and for r=1, since there is no charge inside a spherical gaussian surface, there is no flux density on the surface so D=0 but for r=5m, I assumed a gaussian surface (a sphere) of radius 5. I know the flux at 5m is the same as in part b, 120pi. so:
flux = Qenc = surface integral D dot ds, D and ds are both vectors.
How could I, and the book, assume D is constant and take it outside the integral sign?
The charge density inside the sphere was given as 10/r^2, which isn't uniform over the volume?
How could a sphere be perpindicular to the flux lines contain within when the charge density is not uniform?
However I am second guessing what I did,
This is the problem:
let rho v be 10/r^2 mC/m^3 between 1<r<4
let rho v be zero elsewhere
a)find the net flux crossing the surface at r=2 m, r= 6m
b)determine D at r=1, r=5
a) I have no issues with, I can simply say that the Flux crossing the surface equals the charge enclosed and solve for the charge enclosed by integrating the volume charge density over the volume. I used triple integration in spherical coordinates with r from 1 to 2, theta from 0 to pi, and phi from 0 to 2pi. I got 40pi mC
Same goes for r=6m, I just integrated the same except r went from 1 to 4 (since there is no more charge after r = 4, or rather, the charge density was given as zero) (but the flux will remain the same at 6m as it was at 4m) 120pi
My issue is with what I did in b), applying gauss' law.
I know gauss' law holds, and for r=1, since there is no charge inside a spherical gaussian surface, there is no flux density on the surface so D=0 but for r=5m, I assumed a gaussian surface (a sphere) of radius 5. I know the flux at 5m is the same as in part b, 120pi. so:
flux = Qenc = surface integral D dot ds, D and ds are both vectors.
How could I, and the book, assume D is constant and take it outside the integral sign?
The charge density inside the sphere was given as 10/r^2, which isn't uniform over the volume?
How could a sphere be perpindicular to the flux lines contain within when the charge density is not uniform?