- #36
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This is not true. There are extensions of ##\mathbb{C}##. The division algebras ##\mathbb{H}## and ##\mathbb{O}## have already be named. But you can also add a new transcendental number, say ##T##, so ##\mathbb{C}[T]## which is the same as the polynomial ring over ##\mathbb{C}## first becomes an integral domain, and thus has a quotient field ##\mathbb{C}(T)##, which is a strict field extension of the complex numbers. And you can repeat this process as often as you want. The correct wording is: "... has no proper algebraic field extension!" Both restrictions are necessary as the examples I mentioned show.fbs7 said:"F is algebraically closed field if every non-constant polynomial has a root"... which it says it is equivalent to saying that "F has no proper extension".